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About Scott A Wilson
Expertise
Story problems with any relation to math.

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I started doing story problems in grade school and have been helping people ever since.

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BA in Mathematical Sciences from OSU. MS in Mathematics from OSU

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Both my BS and MS degree were with honors.

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You are here:  Experts > Science > Math for Kids > Word Problems > Fractions

Word Problems - Fractions


Expert: Scott A Wilson - 11/1/2009

Question
Hello:

I sent you this question recently, and I have a follow-up question that follows your answer to my first question.

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2/3 of Mary’s age equals Sarah’s age and 3/4 of Ruth’s age equals Sarah’s age. If the total ages equal 46, how old is each girl?

Answer: Mary 18, Ruth 16, Sarah 12

Solution:

3/2 of Sarah’s age equals Mary’s age.
4/3 of Sarah’s age equals Ruth’s age.
6/6 of Sarah’s age equals Sarah’s age.

46 divided by 23/6 equals Sarah’s age of 12.

Can the following similar situation be solved if the two girls ages do not equal Sarah’s age?

2/3 of Mary’s age equals Ruth’s age and 3/4 of Ruth’s age equals Sarah’s age. How old is each girl?

Their ages may not be the same as those in the above example.

I thank you for your reply.

----------------------- Answer

2M/3 = R, 3R/4 = S, so putting R in gives 3(2M/3)/4 = S, so M/2 = S, so M = 2S.
Also, it can be seen that R = 4S/3.

The sum of the ages is still 46.

Since this time we have M+R+S=46, we can put in what M and R are.

This says 2S + 4S/3 + S = 46, so 6S/3 + 4S/3 + 3S/3 = 46.
this gives 13S/3 = 46, or S = 3*46/13, or S = 138/13 = 10 8/13.

R is (4/3)S = (4/3)(138/13) = 184/13 = 14 2/13.

M is 2S = 2(138/13) = 276/13 = 21 3/13.

M+R+S=(276+184+138)/13 = 598/13 = 46.

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Can the same method for determining the ages in the above examples be used to determine the ages of the girls in the example below?

1/2 of Mary's age and 2/5 of Ruth's age and 1/4 of Mary's age equal 14.  
How old is each girl?

Answers: 10, 15, 12

I thank you for your reply.

Answer
If Mary is M and Ruth is R, is this to say that M/2 + 2R/5 + M/4 = 14?
That would say that 3M/4 + 2R/5 = 14.
Solve the equation for M.  This gives 3M/4 = 14 - 2R/5, or M = 4(14 - 2R/5)/3.
This can be changed to M = 56 - 2R/15.

This means is R was 15, M would be 54.
If R was 30, M would be 52.
If R was 45, M would be 50.
If R was 60, M would be 48.

Perhaps the last M is suppose to be an S.

This makes the equation M/2 + 2R/5 + S/4 = 14.
Again, there are multiple solutions.
The equation to use is M = 2(14 - 2R/5 - S/4).

If R was 5, and S was 4, then M would be 22.
If R was 10, and S was 12, then M would be 14.
If R was 15 and S was 8, then M would be 12.

Do you mean to include something else?


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