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Question
Hi. My math question is,
Ten people are competing in a double-elimination chess tournament, that is, a tournament in which a player who loses two matches is out of the tournament. What are the maximum and minimum number of matches that must be played to determine a winner? Thanks for your help.

Answer
When n teams compete in a double-elimination tournament, the minimum numbers of matches is 2n-2 and the maximum is 2n-1.
Unfortunately, I couldn't create an illustration for your question because until now, I'd never heard of a double-elimination tournament (I don't follow competitive sports and games). But the minimum/maximum information was confirmed by several websites.

Each person in the chess tournament constitutes a single team, so there are 10 teams. The minimum number of matches is 18 and the maximum is 19.

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Janet Yang

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Word problems are my favorite type of math questions! I would not feel comfortable answering questions that require specialized knowledge (Physics, Statistics, etc.) because I have not studied these in depth.

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I tutor students (fifth through twelfth grades) and am a Top Contributor on Yahoo!Answers with over 24,000 math solutions.

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Co-author of An Outline of Scientific Writing: For Researchers With English as a Foreign Language.

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I have a Bachelor's degree in Applied Mathematics from the University of California at Berkeley, and a Master of Business Administration degree from The Wharton School.

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George White Elementary School. Homework Help program at the Ridgewood Public Library, Ridgewood, NJ. Individual students.

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