Word Problems/probability


How would i find the probability that two quarters and a nickel are chosen without replacement from a bag of 8 quarters and 12 nickles??

would the probability formula be necessary??

The function is C(a,b) where a is the number of items and b is the number chosen.
Normally, this is written as a parenthesis on two lines with the numbers over each other.
C(a,b) = a!/[(b!(a-b)!].

The formula would be C(8,2) * C(12,1).  That is, (8!/[2!6!])(12!/[1!11!]).

That reduces to (8*7/2)12 = 28*12 = 336.

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Scott A Wilson


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