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Question
QUESTION: simplify:
1) (7^3a/7^8)^5

2)(3^-2x^-1y^3/3xy^-1)^-2

3) (7-2x-x^2)-(x^2-5x+6)

4) xy+7z-5(xy-3z)

5) (a+2)^3

6) (3k^x-p)(2k^x-5p)

Answer
1) 7^3/7^8 = 1/7^5.  This means we have (a/7^5)^5 = a^5/7^25.
That is the same as a^5/1.34107E+21.

2) The inside gives y^4/27x^2.
When that is taken to the -2, the result is 729x^4/y^8.

3)(7-2x-x^2)-(x^2-5x+6) = 7 - 2x - x^2 - x^2 + 5x - 6 = -x^2 - x^2 - 2x + 5x + 7 - 6 =
-2x^2 + 3x + 1.

4) xy + 7z - 5(xy-3z) multiplies out to xy + 7z - 5xy + 15z.
Combining like terms gives -4xy + 22z.

5) (3k^x-p)(2k^x-5p) can be broken down into 3k^x(2k^x-5p) - p(2k^x-5p).
That multiplies out to 6k^(2x) - 15pk^x  +  -2pk^x + 5p^2.
That combines to 6k^(2x) - 17pk^x + 5p^2.

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