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# Word Problems/Need explanation

Question
A man at A observes the angle of
elevation of a balloon to be 30 degrees. He then walks 1000
metres towards the balloon to a point B and finds the
elevation to be 60 degrees. If the balloon has height h
metres and the man had x metres left to walk before he is
directly under the balloon show that h=xtan60º and h= (x
+1000) tan30º and use these two equations to find x.

The height of the opposite side of the triangle is the same in both cases and is the height of the balloon.  The angles involved are 30º and 60º.  The length of the near side is x+1000 and x.

From this, it is known that when the distance is x and the angle is 60º, h/x = tan 60º.
It is also known when the distance is x+1000, the angle is 30º, so we have h/(x+1000)=tan 30º.

Using these two equations, we can solve both for h and get the equations above.
To solve for x, take h = x * tan 60º and put that into the 2nd equation.
This gives (x * tam 60º)/(x+1000) = tan 30º.

To find x, multiply both sides by x+1000, which gets rid of the fraction.
Subtract x * tan 30º from both sides.
Factor the x term out on the left side.
Divide both sides by the multiple of the x term.

Word Problems

Volunteer

#### Scott A Wilson

##### Expertise

I have answered every question that was a story problems that had any relation to math for which an answer existed. I have ever answered some questions which had a vague relation to math, but still related.

##### Experience

My experience is from when I started doing story problems in grade school. I have been assisting, helping, and bringing smiles to many others ever since. Are you the next one?

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In over 850 questions answered to other users. Maybe you're the next one ...

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I received a BA in Mathematical Sciences from OSU and a MS in Mathematics from OSU as well.

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I earned Both my BS degree and MS degree with honors for having such a high grade point average.

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I have answered hundreds and hundreds of students at OSU in the 80's and over 8,500 questions right here, but only a little over 850 of them have been word problems.